Represent character sets as sets of character ranges
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17 changed files with 551 additions and 499 deletions
51
character_set_spec.cpp
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51
character_set_spec.cpp
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#include "spec_helper.h"
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#include "rules.h"
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using namespace rules;
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START_TEST
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describe("character sets", []() {
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describe("computing the complement", []() {
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it("works for the set containing only the null character", []() {
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CharacterSet set1({ '\0' });
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auto set2 = set1.complement();
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AssertThat(set2, Equals(CharacterSet({
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{ 1, -1 },
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}, true)));
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AssertThat(set2.complement(), Equals(set1));
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});
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it("works for single character sets", []() {
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CharacterSet set1({ 'b' });
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auto set2 = set1.complement();
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AssertThat(set2, Equals(CharacterSet({
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{ 0, 'a' },
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{ 'c', -1 },
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})));
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AssertThat(set2.complement(), Equals(set1));
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});
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});
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describe("computing unions", []() {
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it("works for disjoint sets", []() {
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CharacterSet set({ {'a', 'z'} }, true);
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set.union_with(CharacterSet({ {'A', 'Z'} }, true));
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AssertThat(set, Equals(CharacterSet({ {'a', 'z'}, {'A', 'Z'}, })));
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});
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it("works for sets with adjacent ranges", []() {
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CharacterSet set({ {'a', 'r'} }, true);
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set.union_with(CharacterSet({ {'s', 'z'} }, true));
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AssertThat(set, Equals(CharacterSet({ {'a', 'z'} }, true)));
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});
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it("works when the result becomes a continuous range", []() {
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CharacterSet set({ {'a', 'd'}, {'f', 'z'} }, true);
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set.union_with(CharacterSet({ {'d', 'f'} }, true));
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AssertThat(set, Equals(CharacterSet({ {'a', 'z'} }, true)));
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});
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});
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});
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END_TEST
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