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Drop release functions from callback structs

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The caller can just as easily take care of the cleanup explicitly
This commit is contained in:
Max Brunsfeld 2015-09-08 23:24:33 -07:00
parent 7ee5eaa16a
commit ebd60213d9
10 changed files with 29 additions and 51 deletions
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8
src/runtime/parser.c
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@ -17,7 +17,7 @@
#define DEBUG(...) \
if (parser->lexer.debugger.debug_fn) { \
snprintf(parser->lexer.debug_buffer, TS_DEBUG_BUFFER_SIZE, __VA_ARGS__); \
parser->lexer.debugger.debug_fn(parser->lexer.debugger.data, \
parser->lexer.debugger.debug_fn(parser->lexer.debugger.payload, \
TSDebugTypeParse, \
parser->lexer.debug_buffer); \
}
@ -424,12 +424,8 @@ TSParser ts_parser_make() {
void ts_parser_destroy(TSParser *parser) {
ts_parse_stack_delete(parser->stack);
ts_stack_delete(&parser->right_stack);
if (parser->lookahead)
ts_tree_release(parser->lookahead);
if (parser->lexer.debugger.release_fn)
parser->lexer.debugger.release_fn(parser->lexer.debugger.data);
}
TSDebugger ts_parser_get_debugger(const TSParser *parser) {
@ -437,8 +433,6 @@ TSDebugger ts_parser_get_debugger(const TSParser *parser) {
}
void ts_parser_set_debugger(TSParser *parser, TSDebugger debugger) {
if (parser->lexer.debugger.release_fn)
parser->lexer.debugger.release_fn(parser->lexer.debugger.data);
parser->lexer.debugger = debugger;
}